Let's set b equal to a.

Let's set y equal to 0.

We can set them equal to anything.

We had set it equal to 0.

So you set that equal to 0.

And let's set x5 equal to 0.

You can just set this equal to 0 and it's equal to 6.

We just set product to be equal to 1, so we just set.

So let's set them equal to each other.

You can set y is equal to 0.

You can't set x is equal to 0.

We're going to set that equal to 0.

So let's set them equal to each other.

We can set cosine of t equal to something in x, and we can set sine of t equal in something in y.

So let's set this equation as equal to 0.

So let's set x3 is equal to minus 1.

And we want to set this derivative equal to zero.

We have a quadratic expression being set equal to 0.

And we could set that as equal to what? a.

Well both of these are equal to a so we could set them equal to each other.

Because I can set these guys to be equal to any value. So what is that equal to?

So I set y equal to 0 and I get this.

Let me just set c is equal to 1 over y.

I just set y is equal to 0 right there, right?

If you have a bunch of free variables, you can set all of them but one to equal 0, and then that one that you didn't set to 0, you set it to equal negative 1.

So let's set x equal 0, so you get 2y plus 1 3, times 0 is equal to 12.

And I get the set B3 is equal to a1, a2, a3.

Then these would be free, we can set them equal to anything.

So let's set z cubed minus 2z squared is equal to 0.

This is equal to the set of all the transformations of x.

That my solution set is equal to some vector, some vector there.

To do that, we set the function equal to zero, because this is the point y is equal to 0.

So you set y is equal to 0, and you get 0 is equal to 12x squared minus 5x minus 2.

So let set this equal to a variable, let me call this x.

So just like we did over here, lets set this equal to x.

Rn is equal to the set of all n tuples, ordered n tuples.

For the solution set is everything less than or equal, so we can it could be equal to 32, or less than.

Now, the one thing that we've done over and over again, we know that the solution set of this equation, the solution set of Rx is equal to 0, is the same as the solution set of Ax is equal to 0.

So just like the last problem, I like to set y equal to this.

If you set x, y, and z equal to 0, it satisfies this equation.

And when we set that equal to zero, we got the exact same equation.

You can set y equal to 0 and then you could solve for it.

So let's set that equal to 0, and then solve this problem right there.

And the minimum or maximum point are going to be where this is equal to 0, so let's set that equal to 0.

If we want to set, if the only place that this can equal to 0 is if this numerator is equal to 0.