) If the fair value is less than carrying value (impaired), the goodwill value needs to be reduced so the carrying value is equal to the fair value.

And if we already have a negative value here and if we subtract from that negative value we'll definitely have a negative value here

Then you divide by a negative value. You'll get a positive value

I'm going to get the same function value at the negative value.

Since there's 5 times the absolute value of negative 2 minus 3, the absolute value of negative 2 is positive 2.

I can get to any negative value if I make x negative enough.

But then take the negative value of it.

So that's where that negative value comes from, because it has a negative velocity.

We have a negative x value, our x value is negative, so we're gonna move to the left, we're gonna be on this side.

If the step is negative, the start value must be greater then the end value.

I wanted this to be a positive x value instead of a negative x value.

And then as you lowered your x value, here, you had a smaller negative value.

All we care about is this value positive or negative.

So its x value is going to be negative 4.

Because negative 2 has an absolute value less than 3.

And since we have a negative in the denominator, we want have a negative value up here

This value right here is going to be negative, and then when you subtract from a negative, it's definitely going to be negative.

We've got a negative value, and I divide that by 9.8

And then finally, we have the absolute value of negative 3.

So let me reenter that. Let me do the negative value

The absolute value of negative 11, only 11 away from 0.

So this is equal to the absolute value of negative 4.

So it's the same thing as the absolute value of negative 10.

The absolute value of x is the same thing as negative x.

So we care about the time where this is a negative value

But if it gets too far negative, if it goes to negative 3, we're cool, negative 4, negative 5, negative 6, negative 7, we're still cool, but then at negative 8, all of a sudden the absolute value isn't going to be less than this.

Then they have if x is 2, then our value is negative 2.

What is the absolute value of x if x is a negative number?

So we look at the negative value, because I want the positive time

If I had a negative value, it would be going to the left.

If this was any other non negative value, you would have two values.

Well the absolute value of x, if x is a negative number, is going to be the negative of x, right?

So for every other value other than negative 1, the value of this, of f of x, is equal to 2.

Well, our starting x value is that right over there, that's that negative 3.

But how to figure out the absolute value of that negative number, it's distance.

This is implicitly saying that the absolute value of y has to be negative.

We have 5 times the absolute value of negative 1 plus 3 minus 3.

If we're dealing with negative numbers, then taking the absolute value of a negative number is the same thing as multiplying that negative number times the negative to essentially make it into a positive number, right?

That is d squared, and we don't have to put an absolute value here, because even if d is a negative value, d squared will still be a positive value.

If you try the positive version you'll get a negative value for this entire thing

I'm going to subtract 12 from it, but I could get to any negative value.

So you'd say that the absolute value of negative 3 is equal to positive 3.

So the absolute value of 8 minus 12, which is negative 4, is positive 4.

And then when you add it to negative b you're going to get one value for the numerator, and when you subtract it from negative b you are going to get another value in the numerator.

When x is equal to 2, this value is going to give us negative 1 2 times 2, which is negative 1, minus 2, is going to give us negative 3.