So times 1 over x over 1 over x.

And we get 1 over 1 minus 1 2.

And then plus 1 minus 1 over plus 1 minus 1 over 1, well, that's just going to be another 0.

So times 1 over n plus 1.

So that's 1 plus 1 over n.

Cosine of 0 is 1, so we have minus 1 over s squared, minus 1 over s squared, times 1.

2 times negative 1 plus 2 over negative 1 plus 1.

It's s minus 1 over s minus 1 squared plus 1.

This is 1 factorial over s to the 1 plus 1.

So that is equal to 1 over right, cosine of 0 is 1 over 2 times 1.

Over 1 00?

It's just 1 over s squared plus 1.

It's 1 3 over s squared plus 1.

It's just 1 over s squared plus 1.

Transform is 1 over s squared plus 1.

So minus 1 2 times 1 over x0.

Instead of writing 1 over Bill we would write, so plus 1 over

So we get the strange, undefined 1 over 0 minus 1 over 0.

We have a minus 1 over 4 x0, minus 1 over 4 x0.

Equals a to the n plus 1 minus 1 over a minus 1.

So it's negative 1 over 10 x, and then negative 1 over 10 times negative 10 is plus 1.

So x 1 is right over here. x 1.

This 1 over x times x, that's a 1.

And you have a plus another 1 over 1.

Or 1 over 4A.

It's 1 over sine.

So 1 over 8..

That's 5 over 1.

Minus 1 over 2.

1 over delta x.

Yes. Over 1 00.

So that becomes a 1 plus 4 over x plus 1 over x squared.

That is equal to 1 over 1 over the length of v times v.

So plus 2 times s over s squared plus 1, plus last one plus 1 over s squared plus 1.

We go over here fibbonacci of(2) fibbonacci(1) fibbonacci(0) 1 fibbonacci(2) 1 0 is 1

So if you multiply the 1 out, you get 1 3 times 1 over s squared plus 1 I'm just multiplying the 1 out minus 1 6 these are all the 1's times the 1 times 2 over s squared plus 4.

Over 1 billion people make less than 1 a day

So it becomes 3 times 2 times 1 over 1.

We go over to fibonacci of 1, this is 1

1 over the square root of 5 times 2, 1.

Danny, you've dug 1 7 tunnels. Over 1 7 tunnels.

The inverse Laplace transform of alpha over s squared, plus alpha squared, times 1 over s plus 1 squared, plus 1.

Or you could get.. This is the same thing as 1 over... 1 over 180.

So 1 over the square root of 2 times the vector 0, 0, 1, 1.

So it's dot 1 over the square root of 2 times 0, 0, 1, 1.