There's a minus sign.

Put a minus sign.

We have the minus sign here.

We're going to have that minus sign.

So this was a minus sign out here.

And now I can distribute this minus sign.

Treat the minus sign as part of a word

All I did is, I distributed the minus sign.

The chain rule, derivative of cosine is minus sign.

And then we could have distributed the minus sign.

And I can just leave this as a minus sign.

So you end up with minus 20 under the radical sign.

So here, I have a minus sign, I have multiple variables.

So we get 5 plus 5 8, and then we distribute the negative sign, minus 2 minus 1 5.

We can distribute the negative sign, so we get x squared minus x minus 2 is equal to 4.

So minus all of this, but we already have a minus sign here, so we could write a plus.

And then when you apply the minus sign, it becomes this cofactor.

And to some degree, since we have plus or minus down here, this minus sign kind of doesn't matter, right?

The other one would have been if you had a minus sign here.

So the first thing you want to do is distribute this minus sign.

So you make this into a b, that into an a, and then make that plus sign into a minus sign.

Well we can make this a minus, we can make this a minus sign of x and make this a plus.

And then we can distribute this minus sign, so it's going to be plus.

The other one would be if the minus sign was the other way around.

The second quadrant intersection will be where we take the minus sign right there.

So we'll put that minus sign there so that we haven't fundamentally changed the expression.

There's a minus sign in there, so it would be a really big negative number.

but if you instead of this, if you just put a minus sign right here.

And then minus 4 just keep switching the sign times the determinant of its sub matrix.

If this was a minus then we'd have to distribute the negative sign, but it's not.

And then we want to distribute this minus sign, or multiply all of these terms by negative 1 because we have the minus out here.

So each base is going to be sin of pi x, minus this function, so minus x to the third, plus 4x, right switch the sign.

Cosine of x you take the derivative, you go to minus sign of x, you take the derivative again then you to minus cosine of x, then you take the derivative again then you get a plus sign of x.

Then you have a minus sign here, so it's plus 4. So this all becomes a plus 4.

If you started with this, and changed the sign of the imaginary part, you would get seven minus five i.

I forgot that minus sign there times our vector D, minus 1, 0 0, 1 our matrix D times 1 5 let me just write the 1 5 out here times 1 5.

Negative sign or minus needs to be the left on the number line. So we are going to 46 to the left.

Plus, minus, plus, minus, plus, minus, plus, minus, plus.

Or if you wanted to refer to both the positive and the negative, both the principal and the negative square roots, you'll write a plus or a minus sign in front of the radical sign.

Minus 1 minus 2 times 1 that's minus 1 minus 2 is minus 3.

plane sign, plane sign

The sign. The sign.

OK, then you have 2 minus 4, which is minus 2, minus 2, which is minus 4, minus 4 all right, now minus 2 minus 2, minus 4, and that's minus 8.

Minus 2, minus 2, 1. Minus 2, minus 2 and 1.

Minus 6, minus 16, that's minus 22.