I'm going to add some NaOH.

Sodium hydroxide in an aqueous solution.

Let's say sodium hydroxide.

So if I take some lithium hydroxide in an aqueous solution.

So the NaOH disassociates completely in an aqueous solution.

At first the KOH will cut two inverse pyramids side by side.

Because sure, when you put the sodium hydroxide there, it just ate up all of the hydrogens.

So if you think about what's happening, if I just threw this sodium hydroxide in water.

And of course that water that it grabbed from is not going to be an OH.

As the etching continues the KOH begins to dissolve the silicon between these holes.

It can be prepared by heating mixture of benzil, alcohol and potassium hydroxide.

This lithium hydroxide, when it goes into water There's a couple of ways to think of it.

The sample requires 34.47 milliliters of 0.485 molar sodium hydroxide to reach the equivalence point.

The KOH dissolves silicon faster in the vertical than in the horizontal direction.

So you all of a sudden immediately increase the quantity of OHs by essentially the number of moles of sodium hydroxide you're adding, and you'd immediately increase the pH, right?

And it's a weak base because it likes to accept hydrogen from water, leaving the water with just a hydroxide.

The protective group can be removed by heating the compound in a solution of potassium hydroxide in propan 2 ol (a retro Favorskii reaction).

Well, this is essentially creating a hydroxide molecule out of the surrounding medium so it looks basic, but if you think about it, these reactions are the same.

Empirically, engineers noticed that if they pour potassium hydroxide on a particular surface of crystalline silicon it would eat away at the silicon until it forms a pyramidal shaped hole.

Outside of red blood cells, good ferrous iron the only oxygen carrying form is oxidized uncontrollably to form the bad ferric and ugly ferryl forms of hemoglobin.

But if you do it here if you apply the sodium hydroxide to this solution, the solution that contains a weak acid and it's conjugate base, the weak acid and its conjugate base, what happens?

So for example, if you had 1 mole oh hydrogen molecules in your solution and you added 1 mole of sodium hydroxide to your solution, right when you do that, all this is going to react with all of that.

Synthesis It can be prepared via following reactions Neutralization CsOH (aq) HBr (aq) CsBr (aq) H2O (l) Cs2(CO3) (aq) 2 HBr (aq) 2 CsBr (aq) H2O (l) CO2 (g) Direct synthesis 2 Cs (s) Br2 (g) 2 CsBr (s)The direct synthesis is a vigorous reaction of caesium with other halogens.