The Value of a Pale Blue Dot

Black point valueSpecify specific black point value of the output image.

White point valueSpecify specific white point value of the output image.

It's going to give you the value of the slope of the curve at that point.

Is the center of this hyperbola is at the point x is equal to minus one.

This larger x value we started with this point on the top, so we have to start with this point on the bottom.

I'm just saying, if we go from that point to that point, our y went down by 6, right?

That shows that I only have one y value at that point.

It's going to have to be on the same vertical as this point, which means it's going to have the same x value as this point.

The slope at any point of that line is equal to the x value is equal to the function at that point, not the x value.

The value of the fixed point is fairly precisely determined in the Standard Model, leading to a top quark mass of 230 GeV.

White pointUse a specific white point value to decode RAW pictures. If you set this option to off, the White Point value will be automatically computed.

The slope of the secant line is equal to the value of the function at this point, f of x naught plus h, minus the value of the function here, mine f of x naught.

So it's the y value of the point that's a little bit further away from x.

This leads to a fixed point where the top mass is smaller, 170 200 GeV.

If I take this point I'm just moving to the right a little bit, I'm just increasing my x value the slope will

We know x is what? x is, at this point in time, 8 meters.

Then when I brought my x value in, when I lowered my x value, my x value here, because this is the next point, right here, my x value at the intersection here, went actually, their wording is bad.

If you take your x, you evaluate the function at that point, you're going to get x squared.

least at that point in time while the x value is increasing at 4 meters per second, the y value is moving even faster downward.

Then if you lower and lower the x value, if you lower it enough, you pass the extreme normal line, and then you get to this point, and then this point, he intersects, or actually, you go to this point.

No matter what the initial starting value of the coupling is, if it is sufficiently large it will reach this fixed point value.

And then when t increases a little bit more when we're at t is equal to pi we're at the point minus 3, 0.

Black pointUse a specific black point value to decode RAW pictures. If you set this option to off, the Black Point value will be automatically computed.

And then the y value is what happens to the function when you evaluated it at a, so that's that point right there.

So if you pull in your x value enough, you once again intersect at that same point in the second quadrant.

Now, we can evaluate this and figure out the zeros of this, but the real point why I wanted to show you this is because we always have two solutions.

And then what is f of 0, just so we know, because we want to graph that point? f of 0.

It's going to have the same vertical value or the same y value as point A. So its y coordinate is going to be 1.

So if we keep lowering our x value in the first quadrant, so we keep on pulling in the first quadrant, as we get to this point.

Essentially the graph is monotonic from this point to this point and this point to this point.

Like that point and that point.

But sometimes what you have is this sweet spot in the middle that actually is a combination of technical and market insights that makes for a killer value proposition.

let's call that point A, lets call this point B, and let's call this point C right over here.

So that's the point 6,4.

It's this point and this point.

So, if this point right here is the point, and we already showed that, this is the point the center of the ellipse is the point 1, minus 2.

Whatever the x value is you just put into this f prime of x function or the derivative function, and you'll get the slope at that point.

And we know it goes through that point and we know it goes through that point.

How far is this point from that point?

This little dot right here, this little dot, which is the Earth, this speck this speck...

This was the point over here, the point 3,9.

The dot!

The fact that the line contains this point means that the value x is equal to 4 5, y is equal to 0 must satisfy this equation.

So now, you give me an x value in here, I'll apply this formula over here, and then I can tell you the slope at that point.